Alpha800 wrote:Ian Stewart wrote:
we get 2 eqns, 2 unknowns:
j = 2s + 4
j = 4s - 12
0 = 2s - 16
8 = s
20 = j
Ian, two followups please:
1) how did you get 0 = 2s - 16.
Where did you extract that info from?
2) how do I remember to setup the equation as j-4 =
4(s-4) and
not j-4 =
4s-4
I am tempted to subtract 4 years from 4s. :(
Thanks!
1) I was solving the 2 equations, 2 unknowns- I subtracted the first equation from the second. So really, I was thinking of the two equations like this:
j = 4s - 12
j = 2s + 4
and subtracting. Of course, since j is equal both to 4s - 12 and to 2s + 4, you could also simply solve:
4s - 12 = 2s + 4
2s = 16
s = 8
2) It is easy to make such mistakes on these kinds of questions. I ask myself 'what quantity is equal to 4 times what quantity?'
--> '
Jim's age four years ago (j-4) is equal to 4 times
Sam's age four years ago (s-4)', so
(j-4) = 4(s-4)
Hope that helps!
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