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Over a four-game stretch, Dennis's bowling scope average 240

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by BTGmoderatorDC » Thu Nov 15, 2018 5:56 am

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Over a four-game stretch, Dennis's bowling scope average 240. By what percent would his score have had to have been higher in order for him to average a perfect game (300)?
A) 22%
B) 25%
C) 20%
D) 40%
E) 60%

OA B

Source: Veritas Prep
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Source: — Problem Solving |

by Brent@GMATPrepNow » Thu Nov 15, 2018 6:22 am
BTGmoderatorDC wrote:Over a four-game stretch, Dennis's bowling scope average 240. By what percent would his score have had to have been higher in order for him to average a perfect game (300)?
A) 22%
B) 25%
C) 20%
D) 40%
E) 60%

OA B

Source: Veritas Prep
In other words, an increase from 240 to 300 represents what kind of percent increase?

Percent increase = (100)(new - old)/old
= (100)(300 - 240)/240
= (100)(60)/240
= (100)(1/4)
= 25%

Answer: B

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by fskilnik@GMATH » Thu Nov 15, 2018 8:26 am
BTGmoderatorDC wrote:Over a four-game stretch, Dennis's bowling scope average 240. By what percent would his score have had to have been higher in order for him to average a perfect game (300)?
A) 22%
B) 25%
C) 20%
D) 40%
E) 60%
Source: Veritas Prep
$$?\,\,\,\, = \,\,\,\,\Delta \% \left( {240 \to 300} \right)\,\,\, = \,\,\,{{60} \over {240}}\,\,\, = \,\,\,{1 \over 4}\,\,\, = \,\,\,25\% $$

This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
English-speakers :: https://www.gmath.net
Portuguese-speakers :: https://www.gmath.com.br
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by Scott@TargetTestPrep » Sun Mar 31, 2019 10:51 am
BTGmoderatorDC wrote:Over a four-game stretch, Dennis's bowling scope average 240. By what percent would his score have had to have been higher in order for him to average a perfect game (300)?
A) 22%
B) 25%
C) 20%
D) 40%
E) 60%

OA B

Source: Veritas Prep
(300 - 240)/240 x 100 = 60/240 x 100 = 1/4 x 100 = 25 percent

Answer: B

Scott Woodbury-Stewart
Founder and CEO
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