Over a four-game stretch, Dennis's bowling scope average 240

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Over a four-game stretch, Dennis's bowling scope average 240. By what percent would his score have had to have been higher in order for him to average a perfect game (300)?
A) 22%
B) 25%
C) 20%
D) 40%
E) 60%

OA B

Source: Veritas Prep
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by Brent@GMATPrepNow » Thu Nov 15, 2018 6:22 am
BTGmoderatorDC wrote:Over a four-game stretch, Dennis's bowling scope average 240. By what percent would his score have had to have been higher in order for him to average a perfect game (300)?
A) 22%
B) 25%
C) 20%
D) 40%
E) 60%

OA B

Source: Veritas Prep
In other words, an increase from 240 to 300 represents what kind of percent increase?

Percent increase = (100)(new - old)/old
= (100)(300 - 240)/240
= (100)(60)/240
= (100)(1/4)
= 25%

Answer: B

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by fskilnik@GMATH » Thu Nov 15, 2018 8:26 am
BTGmoderatorDC wrote:Over a four-game stretch, Dennis's bowling scope average 240. By what percent would his score have had to have been higher in order for him to average a perfect game (300)?
A) 22%
B) 25%
C) 20%
D) 40%
E) 60%
Source: Veritas Prep
$$?\,\,\,\, = \,\,\,\,\Delta \% \left( {240 \to 300} \right)\,\,\, = \,\,\,{{60} \over {240}}\,\,\, = \,\,\,{1 \over 4}\,\,\, = \,\,\,25\% $$

This solution follows the notations and rationale taught in the GMATH method.

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Fabio.
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by Scott@TargetTestPrep » Sun Mar 31, 2019 10:51 am
BTGmoderatorDC wrote:Over a four-game stretch, Dennis's bowling scope average 240. By what percent would his score have had to have been higher in order for him to average a perfect game (300)?
A) 22%
B) 25%
C) 20%
D) 40%
E) 60%

OA B

Source: Veritas Prep
(300 - 240)/240 x 100 = 60/240 x 100 = 1/4 x 100 = 25 percent

Answer: B

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