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If a rectangular box has two faces with an area of 30

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by M7MBA » Mon Jul 02, 2018 1:19 am

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If a rectangular box has two faces with an area of 30, two faces of area 60, and two faces of area 72, what is its volume?

A. 60
B. 90
C. 162
D. 300
E. 360

The OA is E.

Should I set a system of 3 equations here? Or, what should I do? I'd appreciate some help.
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Source: — Problem Solving |

by GMATGuruNY » Mon Jul 02, 2018 1:58 am
M7MBA wrote:If a rectangular box has two faces with an area of 30, two faces of area 60, and two faces of area 72, what is its volume?

A. 60
B. 90
C. 162
D. 300
E. 360
Let LW = 72 such that L=6 and W=12.
Since the other two given areas are 30 and 60, H=5:
LH = 6*5 = 30.
WH = 12*5 = 60.
Thus:
V = LWH = 6*12*5 = 360.

The correct answer is E.
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by Vincen » Mon Jul 02, 2018 3:09 am
M7MBA wrote:If a rectangular box has two faces with an area of 30, two faces of area 60, and two faces of area 72, what is its volume?

A. 60
B. 90
C. 162
D. 300
E. 360

The OA is E.

Should I set a system of 3 equations here? Or, what should I do? I'd appreciate some help.
Hello M7MBA.

Here is a fast way to solve this PS question.

We know the following: $$\left(1\right)\ \ \ \ W\cdot L=30$$ $$\left(2\right)\ \ \ \ W\cdot H=60$$ $$\left(3\right)\ \ \ \ L\cdot H=72$$ Now, let's calculate the volumen squared, that is to say, $$V^2=\left(W\cdot L\cdot H\right)^2=W\cdot W\cdot L\cdot L\cdot H\cdot H$$ $$=\left(W\cdot H\right)\cdot\left(W\cdot L\right)\cdot\left(L\cdot H\right)$$ $$=\left(60\right)\cdot\left(30\right)\cdot\left(72\right)$$ $$=129600.$$ $$\Rightarrow\ \ \ V=\sqrt{129600}$$ $$\Rightarrow\ \ \ V=360.$$ Therefore, the correct answer is the option E.

I hope it helps you. <i class="em em-smiley"></i>
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by GMATGuruNY » Mon Jul 02, 2018 4:20 am
Vincen wrote:Hello M7MBA.

Here is a fast way to solve this PS question.

We know the following: $$\left(1\right)\ \ \ \ W\cdot L=30$$ $$\left(2\right)\ \ \ \ W\cdot H=60$$ $$\left(3\right)\ \ \ \ L\cdot H=72$$ Now, let's calculate the volumen squared, that is to say, $$V^2=\left(W\cdot L\cdot H\right)^2=W\cdot W\cdot L\cdot L\cdot H\cdot H$$ $$=\left(W\cdot H\right)\cdot\left(W\cdot L\right)\cdot\left(L\cdot H\right)$$ $$=\left(60\right)\cdot\left(30\right)\cdot\left(72\right)$$ $$=129600.$$ $$\Rightarrow\ \ \ V=\sqrt{129600}$$ $$\Rightarrow\ \ \ V=360.$$ Therefore, the correct answer is the option E.
Nice approach.
Just one suggestion:
Rather than calculate the product of 60, 30 and 72, break the factors into perfect squares, as follows:

V² = 30 * 60 * 72
V² = 30 * 30 * 2 * 2 * 36
V = √(30*30) * √(2*2) * √(6*6)
V = 30*2*6 = 360.
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My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

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I unlock the best way for YOU to solve problems.

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by Scott@TargetTestPrep » Wed Jul 04, 2018 6:14 pm
M7MBA wrote:If a rectangular box has two faces with an area of 30, two faces of area 60, and two faces of area 72, what is its volume?

A. 60
B. 90
C. 162
D. 300
E. 360
Since the volume of a box is V = l x w x h and the area of one of its face is the product of two of the three dimensions, we can assume that l x w = 30, l x h = 60 and w x h = 72. From the three equations, we can see that the only numbers that satisfy them are 5, 6 and 12. That is, 5 x 6 = 30, 5 x 12 = 60 and 6 x 12 = 72. Therefore, the volume of the box is V = 5 x 6 x 12 = 360.

Alternate Solution:

Let's assume that l x w = 30, l x h = 60 and w x h = 72.

Let's multiply these values together:

(l x w) x (l x h) x (w x h) = 30 x 60 x 72

l^2 x w^2 x h^2 = 3 x 10 x 6 x 10 x 8 x 9

(l x w x h)^2 = 3 x 10 x 3 x 2 x 10 x 8 x 9

(l x w x h)^2 = 3^2 x 10^2 x 4^2 x 3^2

l x w x h = 3 x 10 x 4 x 3 = 360

Since l x w x h is the volume of the rectangular box, the volume is 360.

Answer: E

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