Over a four-game stretch, Dennis's bowling scope average 240. By what percent would his score have had to have been high

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Over a four-game stretch, Dennis's bowling scope average 240. By what percent would his score have had to have been higher in order for him to average a perfect game (300)?

A) 22%
B) 25%
C) 20%
D) 40%
E) 60%

Answer: B

Source: Veritas Prep
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Dennis present Bowling Average = 240
A perfect game average = 300
Dennis needs 60 more average point to get perfect game average
So, % increase = $$\frac{60}{240}\cdot100\ =\ 25\%$$ $$Answer\ is\ Option\ B$$

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Gmat_mission wrote:
Fri Nov 20, 2020 1:42 am
Over a four-game stretch, Dennis's bowling scope average 240. By what percent would his score have had to have been higher in order for him to average a perfect game (300)?

A) 22%
B) 25%
C) 20%
D) 40%
E) 60%

Answer: B

Source: Veritas Prep
In other words, an increase from 240 to 300 represents what kind of percent increase?

Percent increase = (100)(new - old)/old
= (100)(300 - 240)/240
= (100)(60)/240
= (100)(1/4)
= 25%

Answer: B

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Brent
Brent Hanneson - Creator of GMATPrepNow.com
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Gmat_mission wrote:
Fri Nov 20, 2020 1:42 am
Over a four-game stretch, Dennis's bowling scope average 240. By what percent would his score have had to have been higher in order for him to average a perfect game (300)?

A) 22%
B) 25%
C) 20%
D) 40%
E) 60%

Answer: B

Solution:

(300 - 240)/240 x 100 = 60/240 x 100 = 1/4 x 100 = 25 percent

Answer: B

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