Find the range of values of \(x\) such that \(\dfrac{(x+6)(3x-4)^3}{(x+2)^2}>0.\)

A. \(x > \dfrac43\)

B. \(\left(-6, \frac43\right)\)

C. \(\left(-\infty, \frac43\right) \cup (6, +\infty) - \{-2\}\)

D. \((-\infty, -6 ) \cup \left(\frac43, +\infty\right)\)

E. \((-\infty, -6) \cup \left(\frac43, +\infty\right) - \{-2\}\)

Answer: D

Source: e-GMAT