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N is the 36th prime number. N has remainder 1 when it is div

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by Max@Math Revolution » Wed Jun 13, 2018 1:43 am

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[GMAT math practice question]

N is the 36th prime number. N has remainder 1 when it is divided by 3 and it has remainder 1 when it is divided by 5. What is the remainder when N is divided by 2?

A. -1
B. 0
C. 1
D. 2
E. 3 $$$$ $$$$
Last edited by Max@Math Revolution on Wed Jul 04, 2018 2:32 pm, edited 2 times in total.
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by GMATGuruNY » Wed Jun 13, 2018 2:37 am
Max@Math Revolution wrote:[GMAT math practice question]

N is the 36th prime number. N has remainder 1 when it is divided by 3 and it has remainder 1 when it is divided by 5. What is the remainder when N is divided by 2?

A. -1
B. 0
C. 1
D. 2
E. 3
The 36th prime number must be ODD.
When an odd number is divided by 2, the remainder is 1.

The correct answer is C.

A remainder must be a nonnegative integer.
If this problem were to appear on the GMAT, option A -- a negative integer -- would not be offered as an answer choice.
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by Max@Math Revolution » Fri Jun 15, 2018 12:53 am
=>

All prime numbers but 2 are odd integers.
Thus, the remainder when N is divided by 2 is 1.

Therefore, the answer is C.
Answer: C
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by Jeff@TargetTestPrep » Mon Jun 18, 2018 11:01 am
Max@Math Revolution wrote:[GMAT math practice question]

N is the 36th prime number. N has remainder 1 when it is divided by 3 and it has remainder 1 when it is divided by 5. What is the remainder when N is divided by 2?

A. -1
B. 0
C. 1
D. 2
E. 3
Since the 36th prime number must be odd, when divided by 2, the remainder is 1.

Answer: C

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