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For 32.45 x 10^k to be less than 1, we need to move the decimal between 2 and 4 two places to the left. For that to happen, we must at least divide 32.45 by 100. Thus, the greatest integer value of k would be -2.swerve wrote:What is the greatest integer \(k\) for which \(32.45\cdot 10^{k}\) is less than 1?
A. -2
B. -1
C. 0
D. 1
E. 2
The OA is A
Source: GMAT Prep
swerve wrote:What is the greatest integer \(k\) for which \(32.45\cdot 10^{k}\) is less than 1?
A. -2
B. -1
C. 0
D. 1
E. 2
The OA is A
Source: GMAT Prep
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