ardz24 wrote:If y is odd, is z odd?
(1) xyz = odd
(2) yz = x
What's the best way to determine which statement is sufficient? Can any experts help?
(1) xyz = odd
=> xz = Odd/y => xz = Odd/Odd
Case 1: Say x = 9; y = 3; and z = 1, then xyz = 27 = 0dd. We have z is odd.
Case 2: If Odd/Odd is a fraction. Example, 1/3. Then we have xz = 1/3. If x = 1 and z = 1/3, then z is not Odd. Insufficient.
(2) yz = x
Case 1: If x/y = Odd. For example, 9/3 = 3. Then we have z = 3 = Odd.
Case 2: If x is odd, z is a fraction. Say x = 1 and y = 3, then z = 1/3 = Not Odd. Insufficient.
(1) and (2) together
Both the cases discussed above are applicable here too. Thus, (1) and (2) together is insufficient.
The correct answer:
E
Hope this helps!
-Jay
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