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Expert replies
by shashank.ism » Mon Feb 08, 2010 7:31 am
Which equation can be graphically represented as follow?

a) 8x2 - 15y2= 169
b) 9x2 - 16y2 = 144
c) |(x - 8)(y - 15)| = 12
d) |(x - 9)(y -16)| = 13
e)None of the above
Image


what should be the approach in this type of problem..Its a bit different type of question
The OA is B
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Source: — Problem Solving |

by harsh.champ » Mon Feb 08, 2010 7:47 am
shashank.ism wrote:Which equation can be graphically represented as follow?

a) 8x2 - 15y2= 169
b) 9x2 - 16y2 = 144
c) |(x - 8)(y - 15)| = 12
d) |(x - 9)(y -16)| = 13
e)None of the above
Image


what should be the approach in this type of problem..Its a bit different type of question
The OA is B
Though it is a way difficult problem for those not acquainted with advanced co-ordinate geometry,
It is the equation of a parabola.First 2 are hence ruled out.(They represent eqn.s of hyperbola or ellipse)
We can see that the graphs cut at x=2 and x=-2 .
Putting these values in C and D ,we can get the answer.

Though I am doubtful; whether they do cut at 2/-2 as the figure is not clear.

Shashank ,can you post a higher resolution of the figure.


[spoiler]Over here,I would say E.(considering 2/-2)[/spoiler]
Last edited by harsh.champ on Mon Feb 08, 2010 7:52 am, edited 2 times in total.
It takes time and effort to explain, so if my comment helped you please press Thanks button :)



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by Brent@GMATPrepNow » Mon Feb 08, 2010 7:48 am
shashank.ism wrote:Which equation can be graphically represented as follow?

a) 8x2 - 15y2= 169
b) 9x2 - 16y2 = 144
c) |(x - 8)(y - 15)| = 12
d) |(x - 9)(y -16)| = 13
e)None of the above
Image


what should be the approach in this type of problem..Its a bit different type of question
The OA is B
This question is totally out of scope. What is the source?
Brent Hanneson - Creator of GMATPrepNow.com
Image
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by thephoenix » Mon Feb 08, 2010 8:15 am
shashank.ism wrote:Which equation can be graphically represented as follow?

a) 8x2 - 15y2= 169
b) 9x2 - 16y2 = 144
c) |(x - 8)(y - 15)| = 12
d) |(x - 9)(y -16)| = 13
e)None of the above
Image


what should be the approach in this type of problem..Its a bit different type of question
The OA is B
guys even on a bad day if some one gets this on exam day then any symmetric or linear or i think any graph can be solved just do one thing use the ruler sheet on screen note three to four corresponding points on the line of graph and plug in the eqn given and match the RHS with LHS the ans where these are equal is the correct ans
hence no need to solve or get annoyed for not knowing the eqn

even for geometrical fig in PS one can use this tech...

this not only saves your time it gives u a correct ans too....
HTH
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by shashank.ism » Mon Feb 08, 2010 8:29 am
harsh.champ wrote:
Though it is a way difficult problem for those not acquainted with advanced co-ordinate geometry,
It is the equation of a parabola.First 2 are hence ruled out.(They represent eqn.s of hyperbola or ellipse)
We can see that the graphs cut at x=2 and x=-2 .
Putting these values in C and D ,we can get the answer.

Though I am doubtful; whether they do cut at 2/-2 as the figure is not clear.

Shashank ,can you post a higher resolution of the figure.


[spoiler]Over here,I would say E.(considering 2/-2)[/spoiler]
Harsh I tried to post high resolution figure but when I load it, the picture becomes very small here. But whenever u click the picture, it will be redirected towards a new url https://www.postimage.org/image.php?v=PqU76Vr in a new tab.
So please click on the picture to have a larger view.
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by shashank.ism » Mon Feb 08, 2010 8:40 am
Brent Hanneson wrote:
This question is totally out of scope. What is the source?
The question has been taken from some internet exams on GMAT. But i don't think its very tough, though some mathematical concepts are required. A bit of graphical analysis is too required for the same.
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by Brent@GMATPrepNow » Mon Feb 08, 2010 9:20 am
shashank.ism wrote:
Brent Hanneson wrote:
This question is totally out of scope. What is the source?
The question has been taken from some internet exams on GMAT. But i don't think its very tough, though some mathematical concepts are required. A bit of graphical analysis is too required for the same.
The issue of whether or not the question is tough is irrelevant here. "Tough" as you can imagine, is a very subjective word. For many people, the math portion of the GMAT is very daunting. Posting questions that are out of scope only serves to intimidate people needlessly.

The truth is that this type of question (hyperbolas of all things) would never appear on the GMAT. Since this is a forum that addresses GMAT questions, your question does not belong here. I'm sure there are other math-related forums where questions like this could be posted.
Brent Hanneson - Creator of GMATPrepNow.com
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