solving the solutions

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solving the solutions

by sanju09 » Fri May 29, 2009 1:21 am
How many ounces of a solution that is 30 percent salt must be added to a 50-ounce solution that is 10 percent salt so that the resulting solution is 20 percent salt?

(A) 20
(B) 30
(C) 40
(D) 50
(E) 60
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by scoobydooby » Fri May 29, 2009 3:15 am
let x ounces of solution be added

amount of the salt in the resulting solution: 5+0.30x
amount of the resulting solution: 50+x

given (5+0.30x)/(50+x)=1/5
=>3/2*x-x=50-25
=> x=50

hence, D