According to me , the answer shuld be (B)2/5. Pls tell us the OA?
Here is how i solved it:-
Given radius , r =1
First name the center of circle as O,
Draw a perpendicular from the point R to the base of triangle extending till center of circle.
The perpendicular from the vertex of an isosceles triangle upon its base bisects its base. Also will the perpendicular from the center bisects the sides of rectangle since its inscribed in it.
Area of rectantgle = Area of triangle
w x h = 1/2 x w x (height of perp)
= 1/2 x w x (radius - h/2) [ since the center of circle is center of rectangle]
so, the equation is
wh=(1/2 )w(1-h/2)
h = (1/2)(1-(h/2))
solving for h, we get h=2/5
----- Some correct me if I am wrong -----
BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course
Redeem
Featured Course
Target Test Prep GMAT OnDemand
Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.
- 715+ score guarantee — highest in the industry (99th percentile)
- 52 chapters · 1,500+ lessons · 4,000+ practice questions
- 400 hours of video · 1,500+ instructor-led HD smartboard lessons
- 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
- 24/7 live support + weekly Zoom office hours with GMAT instructors
- TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
- 1,200+ flashcards + AI-powered study assistant & daily calendar
- OnDemand, LiveTeach & GMAT Bootcamp formats available
- Also: GRE, SAT Math & Executive Assessment courses
- MBA Admissions Consulting now available
- 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
- 200,000+ students served
- 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★
5.0
(559 reviews)
130-pt guarantee
$0 to start
then $127/mo
Geo questions from GMAT 800
Source: Beat The GMAT — Problem Solving |
Excellent!
How did it occur to you that you should draw the perpendicular from R to O?
I did not knew to use the center of the rectangle concept. I was trying hard to some how use the radius given but could not use it.
Good Solution Punit
How did it occur to you that you should draw the perpendicular from R to O?
I did not knew to use the center of the rectangle concept. I was trying hard to some how use the radius given but could not use it.
Good Solution Punit
Rule to know to solve this is that the center of the circle is also the center of an inscribed rectangle/square. So when you draw a line from the vertex of the equilateral triangle to the center O it will bisect the base of the triangle.
