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A fudgemaker has 40 pounds of chocolate, 65% of which is dark chocolate. If she buys 10 more pounds of chocolate, 25%

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A fudgemaker has 40 pounds of chocolate, 65% of which is dark chocolate. If she buys 10 more pounds of chocolate, 25%

by BTGmoderatorDC » Fri Aug 21, 2020 6:11 pm

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A fudgemaker has 40 pounds of chocolate, 65% of which is dark chocolate. If she buys 10 more pounds of chocolate, 25% of which is dark chocolate, what percent of her chocolate will then be dark chocolate?

A. 48%
B. 51%
C. 54%
D. 57%
E. 60%


OA D

Source: Veritas Prep
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Re: A fudgemaker has 40 pounds of chocolate, 65% of which is dark chocolate. If she buys 10 more pounds of chocolate, 25

by Targt780 » Sat Aug 22, 2020 2:39 am
Initial weight of the chocolate = 40 pounds

% of dark chocolate in the initial mixture = 65%

Dark chocolate in the initial mixture (pounds) = 65%*40=26 pounds

Additional chocolate purchased (Pounds) = 10 pounds

% of dark chocolate in the additional purchase = 25%

Dark chocolate in the additional chocolate (Pounds) = 25%*10=2.5 pounds

Total chocolate mixture weight (pounds) = 40 + 10 = 50 pounds

Total dark chocolate in the mixture = 26 + 2.5 = 28.5 pounds

% of dark chocolate in the entire mixture = \(\frac{28.5}{50}\) = 57%
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Re: A fudgemaker has 40 pounds of chocolate, 65% of which is dark chocolate. If she buys 10 more pounds of chocolate, 25

by swerve » Sat Aug 22, 2020 3:36 am
BTGmoderatorDC wrote: ↑
Fri Aug 21, 2020 6:11 pm
 A fudgemaker has 40 pounds of chocolate, 65% of which is dark chocolate. If she buys 10 more pounds of chocolate, 25% of which is dark chocolate, what percent of her chocolate will then be dark chocolate?

A. 48%
B. 51%
C. 54%
D. 57%
E. 60%


OA D

Source: Veritas Prep
\(65% of 40 = 26\)
\(25% of 10 = 2.5\)

Total dark chocolate \(= 28.5\)
Total chocolate \(= 10+40 = 50\)

Total \(\%\) of dark chocolate \(= \dfrac{28.5}{50}\cdot 2 = 57\%\)
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