line AC is parallel to y-axis or both A and C have same value of x-axis this means line Ab will also be parallel to the x-axis as A and b have the same value of y-axis and point B =(x,4)
Statement 1
$$Area\ of\ Triangle\ ABC=30$$
$$from\ \frac{1}{2}bh=\frac{1}{2}\cdot AB\cdot AC=30$$
Since point A=4units above x-axis ;AC=5
similarly AB=3+x
therefore,
$$\frac{1}{2}\cdot\left(3+x\right)\cdot5=30$$
$$15+5x=60$$
$$\frac{5x}{5}=\frac{\left(60-15\right)}{5}$$
$$\frac{45}{5}=9$$
x=9 Coordinates of point B=(9,4) statement 1 is SUFFICIENT.
Statement 2
length CB=(13) considering the triangle BAC will be using pythagoras theorem.
$$h^2=O^2+a^2$$
$$BC^2=AB^2+AC^2$$
$$13^2=AB^2+5^2$$
$$AB^2=169-25=144$$
$$AB=\sqrt{144}=12$$
$$AB=12$$
$$3+x=12$$
$$x=12-3=9$$
coordinates of point B=(9,4)
Statement 2 is SUFFICIENT.
Since each statement alone are SUFFICIENT.
$$Answer\ is\ option\ D$$
