Trapezoid \(JKLM\) in the x-y plane has coordinates \(J =(\)

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swerve: Legendary Member; Posts: 2499; Joined: Sun Oct 29, 2017 2:04 pm; Followed by:6 members

Trapezoid \(JKLM\) in the x-y plane has coordinates \(J =(\)

by swerve » Thu Sep 19, 2019 3:57 am

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Trapezoid \(JKLM\) in the x-y plane has coordinates \(J = (-2, -4), K = (-2, 1), L = (6, 7),\) and \(M = (6, -4)\). What is its perimeter?

A. 34
B. 36
C. 38
D. 40
F. 42

The OA is A

Source: Magoosh

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Source: Beat The GMAT — Problem Solving | Thu Sep 19, 2019 3:57 am

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Jay@ManhattanReview: GMAT Instructor; Posts: 3008; Joined: Mon Aug 22, 2016 6:19 am; Location: Grand Central / New York; Thanked: 470 times; Followed by:34 members

by Jay@ManhattanReview » Thu Sep 19, 2019 9:52 pm

swerve wrote:Trapezoid \(JKLM\) in the x-y plane has coordinates \(J = (-2, -4), K = (-2, 1), L = (6, 7),\) and \(M = (6, -4)\). What is its perimeter?

A. 34
B. 36
C. 38
D. 40
F. 42

The OA is A

Source: Magoosh

See the above image. For the trapezoid JKLM, we have JK = 4 + 1 == 5; JM = 6 + 2 = 8; LM = 7 + 4 = 11 and KL = âˆš(8^2 + 6^2 = 10.

Thus, the perimeter of the trapezoid JKLM = 5 + 8 + 11 + 10 = 34

The correct answer: A

Hope this helps!

-Jay
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