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Is xy + xy < xy ?

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Is xy + xy < xy ?

by ronaldramlan » Sun Aug 07, 2011 4:00 am
Is xy + xy < xy ?

(1) x^2/y < 0

(2) x^9(y^3)^3 < (x^2)^4(y^8)


(A) Statement (1) alone is sufficient, but statement (2) alone is not sufficient.
(B) Statement (2) alone is sufficient, but statement (1) alone is not sufficient.
(C) BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
(D) Each statement ALONE is sufficient.
(E) Statements (1) and (2) TOGETHER are NOT sufficient.

I'll post OA after some replies ... :)
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by GmatKiss » Sun Aug 07, 2011 5:24 am
IMO:D :)
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by akhilsuhag » Sun Aug 07, 2011 5:53 am
Prompt:
is xy + xy < xy? = is 2xy < xy? = is xy <0 ?
So this is what the question is basically asking. So either one of them (x or y) has to be negative.

Statement 1:
x^2/y < 0;
x^2 can never be negative; so y is negative.
But even x can be negative. We don't know nethin about x. So Insufficient

Statement 2:
x^9(y^3)^3 < (x^2)^4(y^8)
= x^9.y^9 < x^8.y^8

We know x^8.y^8 can only be positive. We divide both sides with it. This gives us:

xy < 1

Again not enough information. We want is xy < 0. So again Insufficient

Statements Together,

y is negative and xy < 1

Not sufficient because x can be -ve and xy < 1. We can't assume x and y to be integers xy can be 0.6 and 0.4 or -0.6 and -0.4 and still satisfy and conditions.

So Insufficient

So : E

Again I am not an expert just tryin my luck!!
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by akhilsuhag » Sun Aug 07, 2011 5:54 am
Can we have the OA plz!!
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by ronaldramlan » Sun Aug 07, 2011 7:36 am
OA is E
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