Stmt. II is clearly not sufficient.
If both x and y are negative and x>y, then |x|<|y|. for e.g. -2>-3, but |-2|<|-3|
If both x and y are positive and x>y, then |x|>|y|.
As you can see both the statement above gives different relationship between |x| and |y|, clearly B is insufficient.
Is |x|>|y|?
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this_time_i_will
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Solution:
We need to know if lxl > lyl or not.
Consider first (1) alone.
It says x^2 > y^2.
Or (x^2 - y^2) > 0.
Or (x+y)(x-y) > 0.
There can be 2 cases.
Case (1) x+y > 0 and x-y > 0 which is x > -y and x >y.
This means x > 0 and x>lyl.
Or it means lxl > lyl
Case (2) x+y < 0 and x-y < 0 which is x < -y and x < y or -x > y and -x > -y.
This means x < 0 and -x > lyl.
Since lxl = -x if x < 0, we have lxl > lyl.
Since both cases give lxl > lyl, we get (1) alone is sufficient.
Next consider (2) alone.
Let x = 2, y = 1. So lxl = 2 and lyl = 1.
Here x > y and lxl > lyl.
Next let x = -3, y = -4. So lxl = 3 and lyl = 4.
Here x > y but lxl < lyl.
Since nothing definite can be said (2) alone is not sufficient.
The correct answer is (A).
We need to know if lxl > lyl or not.
Consider first (1) alone.
It says x^2 > y^2.
Or (x^2 - y^2) > 0.
Or (x+y)(x-y) > 0.
There can be 2 cases.
Case (1) x+y > 0 and x-y > 0 which is x > -y and x >y.
This means x > 0 and x>lyl.
Or it means lxl > lyl
Case (2) x+y < 0 and x-y < 0 which is x < -y and x < y or -x > y and -x > -y.
This means x < 0 and -x > lyl.
Since lxl = -x if x < 0, we have lxl > lyl.
Since both cases give lxl > lyl, we get (1) alone is sufficient.
Next consider (2) alone.
Let x = 2, y = 1. So lxl = 2 and lyl = 1.
Here x > y and lxl > lyl.
Next let x = -3, y = -4. So lxl = 3 and lyl = 4.
Here x > y but lxl < lyl.
Since nothing definite can be said (2) alone is not sufficient.
The correct answer is (A).
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What if there is a statement x^3>y^3, then |x|>|y| is true because the power is odd, right?
Not necessary.
Take same examples.
Let x = 3 and y = 2.
x^3 = 27 and y^3 = 8. lxl = 27 and lyl = 8
Here x^3 > y^3 and lxl > lyl.
Next let x = -3 and y = -4.
So x^3 = -27 and y^3 = -64. lxl = 3 and lyl = 4.
Here x^3 > y^3 but lxl < lyl.
Hence it is not sufficient.
Not necessary.
Take same examples.
Let x = 3 and y = 2.
x^3 = 27 and y^3 = 8. lxl = 27 and lyl = 8
Here x^3 > y^3 and lxl > lyl.
Next let x = -3 and y = -4.
So x^3 = -27 and y^3 = -64. lxl = 3 and lyl = 4.
Here x^3 > y^3 but lxl < lyl.
Hence it is not sufficient.
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Rahul, thank you so much for such detailed explanation. At some point I thought that everything is clear for me, but then I realized that I'm mixed up with x^2>y^2
Let's take an example:
x=3, y=2
x^2>y^2 as 9>4, then |x|>|y|
if x = -2, y = -3
x>y,
but X^2<y^2, and then |x|<|y|
Could you please tell me where is my mistake, because according to my logic st. A in the first problem is incorrect, but it's not true!
Let's take an example:
x=3, y=2
x^2>y^2 as 9>4, then |x|>|y|
if x = -2, y = -3
x>y,
but X^2<y^2, and then |x|<|y|
Could you please tell me where is my mistake, because according to my logic st. A in the first problem is incorrect, but it's not true!
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Rahul@gurome
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Actually when you are solving Data sufficiency problem, you are not supposed to ascertain whether statements (1) and (2) are correct or not.
You first note what has been asked in the main question?
You then take the statement (1) and try to find out whether you can answer the main question assuming (1) to be true. The same thing is then done for statement (2) and lastly for both statements combined if individually both statements do not give a definite reply.
In your solution you cannot take x = -2 and y = -3 because they are contradicting what is given in the statement (1) which is x^2 > y^2 since (x^2 = 4) < (y^2 = 9)
You need to take x and y such that x^2 > y^2.
Hope it is clearer.
You first note what has been asked in the main question?
You then take the statement (1) and try to find out whether you can answer the main question assuming (1) to be true. The same thing is then done for statement (2) and lastly for both statements combined if individually both statements do not give a definite reply.
In your solution you cannot take x = -2 and y = -3 because they are contradicting what is given in the statement (1) which is x^2 > y^2 since (x^2 = 4) < (y^2 = 9)
You need to take x and y such that x^2 > y^2.
Hope it is clearer.
Rahul Lakhani
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On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
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Quant Expert
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