is 1/(a-b) < b - a?
st1 a < b
st2 1 < absolute value of (a - b)
so statement 1 i was able to prove by picking values
meeting condition of a<b
a = 3 and b = 4
so 1/(3 - 4) =-1 < 4-3
then a = 1/4 and b = 3/4
we get 2 < some fraction which proves st1 not sufficient
my confusion comes in on second statement which basically says that a -b is a number bigger then 1... does this mean that because its not a fraction the left side 1/(a-b) will always be less then b-a?
what if a-b is a mixed number which is possible since we are not constrained to integers?
st1 a < b
st2 1 < absolute value of (a - b)
so statement 1 i was able to prove by picking values
meeting condition of a<b
a = 3 and b = 4
so 1/(3 - 4) =-1 < 4-3
then a = 1/4 and b = 3/4
we get 2 < some fraction which proves st1 not sufficient
my confusion comes in on second statement which basically says that a -b is a number bigger then 1... does this mean that because its not a fraction the left side 1/(a-b) will always be less then b-a?
what if a-b is a mixed number which is possible since we are not constrained to integers?
