BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

ia x negative

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Data Sufficiency |
Junior | Next Rank: 30 Posts
Posts: 12
Joined: Sun Jun 21, 2009 1:27 am
Thanked: 1 times

by ronaldo780 » Sun Sep 13, 2009 4:22 am
Answer choice is E.

At a first glance you can see that both statements have x^2 so they cannot really say anything about the polarity (+/-) of x.

(i) plug in x=2 or x=-2 to get n^3(1-4)<0 or (n^3)(-3)<0; n can be positive so the statement holds, but we don't know whether x is neg or pos.

(ii) x^2-1<0 is x^2<1. plug in x=-1/2 or x=1/2. still no certain polarity.

(i)+(ii) we know 1-x^2 is pos, no matter what x is. so n^3 must be neg, but that's not the question!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 109
Joined: Sun May 10, 2009 7:53 am

by sanjib » Sun Sep 13, 2009 5:27 am
The st.2 is not very clear the way it is explained. Please.
OA is not E
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 1035
Joined: Wed Aug 27, 2008 10:56 pmFollowed by: 1 member
Thanked: 104 times

by scoobydooby » Sun Sep 13, 2009 9:57 am
guess there is a typo.
statement 1 should read x^3(1-x^2)<0
=>x^3<x^5

possible when x>1 or when x is a negative fraction
not sufficient

statement 2: x^2-1<0
=> -1<x<1
not sufficient

together, x must be a negative fraction.
hence, C
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1