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by XLogic » Fri Jan 28, 2011 11:18 pm
Hello,

I'm sure this is an easy question but I'm just starting out. I figured the right answer to the question (eventually) but it took too long to resolve. Please offer a fast strategy for these kinds of problems. Thanks.

QR 2nd Edition, Page 157:

64. If y is an integer, is y^3 divisible by 9?

(1) y is divisible by 4.
(2) y is divisible by 6.
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Source: — Data Sufficiency |

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by Anurag@Gurome » Sat Jan 29, 2011 12:31 am
XLogic wrote:If y is an integer, is y³ divisible by 9?

(1) y is divisible by 4.
(2) y is divisible by 6.
If y is divisible by any positive multiple of 3, then y³ will be divisible by 27 and hence by 9 too.

Statement 1: y may or may not be divisible by 3.

Not sufficient

Statement 2: y is divisible by 3. Hence y³ is divisible by 9.

Sufficient

The correct answer is B.
Anurag Mairal, Ph.D., MBA
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