straightforward

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straightforward

by sanju09 » Wed Sep 15, 2010 1:15 am
Which of the following could be the sum of three consecutive integers?
(A) 29
(B) 46
(C) 57
(D) 92
(E) 100



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by kmittal82 » Wed Sep 15, 2010 1:37 am
Let the 3 integers be x-1, x and x+1

Sum = 3x

Only a number divisible by 3 will satisfy this sum, hence (C)

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by limestone » Wed Sep 15, 2010 1:39 am
Three consecutive integers have the forms of : a, a+1, a+2
in which a is an integer.
The Sum = a + a + 1 + a + 2 = 3a + 3
As seen above, the sum must be divisible to 3.
Only 57 is divisible to 3, hence D must be the answer.
Last edited by limestone on Wed Sep 15, 2010 5:21 am, edited 1 time in total.

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by sanju09 » Wed Sep 15, 2010 2:48 am
limestone wrote:Three consecutive integers have the forms of : a, a+1, a+2
in which a is an integer.
The Sum = a + a + 1 + a + 2 = 3a + 3
As seen above, the sum must be divisible to 3.
[spoiler]Only 57 is divisible to 3, hence D must be the answer.[/spoiler]
sorry, you still need to edit a bit
The mind is everything. What you think you become. -Lord Buddha



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