BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Divisible by 7

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 222
Joined: Mon Oct 13, 2008 4:04 pm
Thanked: 3 times
Followed by:2 members

Divisible by 7

by venmic » Sun Jul 31, 2011 12:48 pm
Need the best approach to solve this problem

How many of the three-digit numbers are divisible by 7?

Thankyou for your help in advance
Top
Source: — Problem Solving |
Senior | Next Rank: 100 Posts
Posts: 49
Joined: Sun Jun 26, 2011 5:45 pm
Thanked: 2 times

by edge » Sun Jul 31, 2011 1:32 pm
You will need to find the first and last 3-digit numbers divisible by 7 (7 x 15 = 105 and 7 x 142 = 994). Number of 'jumps' = (142 - 15 + 1) = 128. This is your answer.
Top
Post new topic Post Reply
• Page 1 of 1