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Source: — Problem Solving |
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by ilikaroy » Sat May 15, 2010 6:56 am
Let the length of the square box between x and 3 be y.
So area of shaded region is 3x+9+3y+3x+9 = 6x+18+3y.
Area of unshaded region is 3y+3x+9+3y = 6y+3x+9.
So 6x+18+3y = 6y+3x+9
Or 3y - 3x = 9
Or y - x = 3.
Or y = 3+x
Also x+y+3 = 9.
Or 3+x+x+3 = 9.
Or 2x = 3
Or x = 3/2 = 1.5
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