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31 - #18

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Re: 31 - #18

by gabriel » Sun Aug 19, 2007 12:17 pm
magical cook wrote:Hi,

Can anyone help?


Thanks,
Hi magical cook,

werent u done with ur gmat .. so wats up with these questions on a gmat forum .. are u giving it again .. nyway welcome back ..

Ok to the question now ..

we have mod(y) < = 12 .. so that basically means y can take values from .. -12 to 12 ..

we also have 2x+y = 12 .. so x = (12-y)/2 ..

so for x to be an integer y has to take even integer values .. from -12 to 12 y can have 13 even integer values .. so there can be 13 ordered pair of(x,y) where both of them are integers .. So the answer is 13
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by magical cook » Mon Aug 20, 2007 7:45 am
Hi gabriel!

Yes...I was just taking a LONG break and started working on GMAT study a few days ago.. While taking break, I bought a lot of questions online, so I would probably post many - appreciate your help in advance!

So, this question, yes the answer is D)

but I found only 12 that would meet the equestion...from -12 -10....0 2...10 (since 12 would be zero?) OR 12 should be included?

Thanks!
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by beny » Mon Aug 20, 2007 8:53 am
y=12, x=0. It works. Include it.
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