IS (x+y)(x-y)>0
From 1 x>|Y|
hence X is positive ..so (x+y) and (x-y) will be both positive...(x+y)(x-y)>0 ..sufficient
From 2
|x|>y
So (x+y)(x-y)>0 ..sufficient
Ans option D
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41) MOD DS
Source: Beat The GMAT — Data Sufficiency |
we can re write the question as
IS (x+y)(x-y)>0
From 1 x>|Y|
hence X is positive ..so (x+y) and (x-y) will be both positive...(x+y)(x-y)>0 ..sufficient
From 2
|x|>y
So (x+y)(x-y)>0 ..sufficient
Ans option D
IS (x+y)(x-y)>0
From 1 x>|Y|
hence X is positive ..so (x+y) and (x-y) will be both positive...(x+y)(x-y)>0 ..sufficient
From 2
|x|>y
So (x+y)(x-y)>0 ..sufficient
Ans option D
"If you don't know where you are going, any road will get you there."
Lewis Carroll
Lewis Carroll
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ballubalraj
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Another way to solve it:
Square of any positive or negative number is always positive. So irrespective of the sign of x and y, as long as x > y (leaving the sign), x^2 - y^2 will always be > 0.
As both the statements say that x > y (leaving the sign part), both statements alone are sufficient.
Answer: D
Square of any positive or negative number is always positive. So irrespective of the sign of x and y, as long as x > y (leaving the sign), x^2 - y^2 will always be > 0.
As both the statements say that x > y (leaving the sign part), both statements alone are sufficient.
Answer: D
Hi,
I agree that statment 1 is sufficient, but i am not sure about 2.
take X = -3 and Y = -4
This means that |x|>y, but, x^2 - y^2 < 0
I agree that statment 1 is sufficient, but i am not sure about 2.
take X = -3 and Y = -4
This means that |x|>y, but, x^2 - y^2 < 0
Can't you just simply square both sides of each statement? That way we don't have to worry about sign changes. Or am I oversimplifying it?
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ballubalraj
- Senior | Next Rank: 100 Posts
- Posts: 66
- Location: Bangalore
- Thanked: 9 times
- GMAT Score:730
I guess November Rain is correct. GMAT always tricks us with simple looking but tricky questions - ineuqalities and modes are probably the best examples.
So the answer should be A.
Any thoughts?
So the answer should be A.
Any thoughts?
Yep...I think that the answer should be A
November Rain's values - -3 and -4 prove that a^2-b^2 can be less than 0.
November Rain's values - -3 and -4 prove that a^2-b^2 can be less than 0.
