300 tough Algebra

This topic has expert replies
User avatar
Legendary Member
Posts: 1665
Joined: Thu Nov 03, 2011 7:04 pm
Thanked: 165 times
Followed by:70 members

by karthikpandian19 » Thu Jun 14, 2012 11:27 pm
Anurag,

It seems your approach is very easy if we understand the concept. Can you explain it again in detail?
Anurag@Gurome wrote:
yellowho wrote:What is the sum of all possible solutions for x of the equation x ( x − k ) = k + 1?

(A) 0
(B) 1
(C) k
(D) k + 1
(E) 2k - 1
Any quadratic equations in x with two roots a and b can be expressed as, (x - a)(x - b) = 0. Which on expansion takes the form, x² - (a + b)x - ab = 0

Hence, the sum of the roots = -(coefficient of x in the expanded form)

Now, x(x − k) = k + 1
=> x² - kx - (k + 1) = 0

Hence, sum of the roots = -(-k) = k

The correct answer is C.
Regards,
Karthik
The source of the questions that i post from JUNE 2013 is from KNEWTON

---If you find my post useful, click "Thank" :) :)---
---Never stop until cracking GMAT---

Senior | Next Rank: 100 Posts
Posts: 58
Joined: Sat Mar 05, 2011 9:14 am
Location: Bangalore
Thanked: 20 times
Followed by:5 members
GMAT Score:770

by gmat_and_me » Fri Jun 15, 2012 5:55 am
Sum of the roots of the equation ax^2 + bx + c = 0
is -b/a

Product of the roots = c/a

roots of such an equation are

(-b + rootof(b^2 - 4ac)) / 2a

and

(-b - rootof(b^2 - 4ac)) / 2a

HTH

User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pm
Location: New York, NY
Thanked: 13060 times
Followed by:1906 members
GMAT Score:790

by GMATGuruNY » Fri Jun 15, 2012 5:56 am
karthikpandian19 wrote:Anurag,

It seems your approach is very easy if we understand the concept. Can you explain it again in detail?
yellowho wrote:What is the sum of all possible solutions for x of the equation x ( x − k ) = k + 1?

(A) 0
(B) 1
(C) k
(D) k + 1
(E) 2k - 1
For any quadratic in the form ax² + bc + c = 0:
The sum of the roots = -b/a.
The product of the roots = c/a.

When x(x−k) = k + 1 is rephrased as x² - kx - (k+1) = 0:
a = the coefficient of x² = 1.
b = the coefficient of x = -k.
c = -(k+1).
Thus, the sum of the roots = -b/a = -(-k)/1 = k.

The correct answer is C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3

Master | Next Rank: 500 Posts
Posts: 171
Joined: Tue Jan 08, 2013 7:24 am
Thanked: 1 times

by rajeshsinghgmat » Sun Apr 28, 2013 5:55 am
(C) k
x= (k+(k+2))/2,(k-(k+2))/2

x= k+1,-1

hence the sum of all possible solutions of x is,
S= k+1 +(-1)
S= k

User avatar
Senior | Next Rank: 100 Posts
Posts: 42
Joined: Tue Dec 06, 2011 8:06 am
Thanked: 3 times
Followed by:1 members

by ygdrasil24 » Sun Apr 28, 2013 7:07 am
I guess its a sitter.Degree of equation is 2, so simply find out sum of roots.
Thanks :)

GMAT Instructor
Posts: 2630
Joined: Wed Sep 12, 2012 3:32 pm
Location: East Bay all the way
Thanked: 625 times
Followed by:119 members
GMAT Score:780

by Matt@VeritasPrep » Sun Apr 28, 2013 6:56 pm
One note of caution: any question easily solved with Vieta's formulas for the sum and product of the roots of a polynomial is not typical of the GMAT. (The GMAT confines itself to Algebra 1, and Vieta is Algebra 2, at the earliest.) This question feels more like one you'd see on the Indian CAT or around the beginning of the AMC 10.

On top of that, this question takes ten seconds with Vieta, violating (something I've found to be) an unwritten GMAT rule: "If a problem can be solved with supra-GMAT math (e.g. algebra 2, trig, calculus), the supra-GMAT solution somehow takes longer than some nifty GMAT-level solution." So don't lose sleep over it!