karthikpandian19 wrote:Anurag,
It seems your approach is very easy if we understand the concept. Can you explain it again in detail?
yellowho wrote:What is the sum of all possible solutions for x of the equation x ( x − k ) = k + 1?
(A) 0
(B) 1
(C) k
(D) k + 1
(E) 2k - 1
For any quadratic in the form ax² + bc + c = 0:
The sum of the roots = -b/a.
The product of the roots = c/a.
When x(x−k) = k + 1 is rephrased as x² - kx - (k+1) = 0:
a = the coefficient of x² = 1.
b = the coefficient of x = -k.
c = -(k+1).
Thus, the sum of the roots = -b/a = -(-k)/1 = k.
The correct answer is
C.
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