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Source: — Data Sufficiency |

by helenec » Sun Aug 01, 2010 5:44 pm
f d is a decimal then d=0.abc

is c>5?

1. d*10 = a.bc
if the tenths digit = 7, c=7 => c>5 suff

1. d/10 = 0.0abc
if the thousand digit = 7, c=7 => c>5 suff
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by HPengineer » Mon Aug 02, 2010 4:57 pm
lets say d is simply .700 since statement 1 says that 7 is in the tenths place.. D * 10 would = 7.00 therefore being insufficient to answer the question..

Obviously im wrong can someone shed some light? Most likely im not interpreting the problem correctly.

Cheers

M
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by KrazyKarl » Mon Aug 02, 2010 10:44 pm
Say you have a decimal:

0.123

and multiply by 10, you'd have 1.23

The original thousands digit, 3, becomes the new hundredths digit; and the original hundredths digit, 2, becomes the new tenths digit.

So statement 1 says, if you multiply by 10, the new tenths digit is 7, which means that it is the old hundredths digit.

I think you're thinking the right way, just the opposite. You need to go the other way - their statement (at least statement 1) is the proposed, hypothetical 10d, which means to get to the actual (original) number you have to divide by 10 to get to just-plain decimal d.
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by lunarpower » Tue Aug 03, 2010 3:53 am
you should think of these multiplications as though the decimal point has moved.
in fact, this is precisely what has happened, as both statements involve multiplication by powers of 10 -- which serves to move the decimal point while leaving the digits themselves unaffected.

here's the deal:
you are interested in the hundredths place of the original number 'd'. to wit, let's write 'd' as a succession of decimal places:
d = XXXXXX.XXXX...
in this version, the orange digit is the one in which you're interested.

statement (1) concerns the number 10d, not d. when you multiply by 10, the decimal point is shifted to the right by one spot, so that the ones digit becomes the new tens digit and so on. so, with 'd' represented as above, you can write
10d = XXXXXXX.XXX...
according to statement (1), then, the orange digit is 7, so statement (1) is sufficient.

statement (2) concerns the number d/10, not d. when you divide by 10, the decimal point is shifted to the left by one spot, so that the tens digit becomes the new ones digit and so on. so, with 'd' represented as above, you can write
d/10 = XXXXX.XXXXX...
according to statement (2), then, the orange digit is 7, so statement (2) is sufficient.

hth.
Ron has been teaching various standardized tests for 20 years.

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by HPengineer » Tue Aug 03, 2010 6:12 am
Thanks to all..... I see the error i made now.. I understood the concept of the decimal moving however i was evaluating 10D as opposed to D.
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