What is the probability of creating a three digit number with exactly two consective primes as digits?
a) 3/100
b) 9/250
c) 9/125
d) 21/250
e) 51/500
a) 3/100
b) 9/250
c) 9/125
d) 21/250
e) 51/500
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Assuming this is the correct interpretation of the question:pops wrote:2 consecutive prime can be 2,3 or 3,5 or 5,7
number of numbers formed with 2,3 = 2^3 however, question is using exactly two consecutive primes so we have to remove the case 222 and 333 hence number of such numbers = 2^3-2 = 6
so, number of such numbers for 2,3..2,5 and 5,7 = 3*6 = 18
number of three digit number = 900
hence, answer is 18/900 = 1/50
none of the answer choice..![]()
but i guess my method is correct !

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