2^5+2^5+3^5+3^5+3^5
2*(2^5)+3*(3^5)=2^(5+1)+3^(5+1)=2^6+3^6
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easy exponents
Source: Beat The GMAT — Problem Solving |
Shouldn't it be - 2^6+3^7
truplayer256 wrote:2^5+2^5+3^5+3^5+3^5
2*(2^5)+3*(3^5)=2^(5+1)+3^(5+1)=2^6+3^6
no. coz 3*3^5=3^(5+1)=3^6mehravikas wrote:Shouldn't it be - 2^6+3^7
truplayer256 wrote:2^5+2^5+3^5+3^5+3^5
2*(2^5)+3*(3^5)=2^(5+1)+3^(5+1)=2^6+3^6
The powers of two are bloody impolite!!
Hi,
Wanna to remind you the very basic formula or property behind this...
(a) ^ (x) * (a) ^ (y) = (a) ^ (x+y).
Wanna to remind you the very basic formula or property behind this...
(a) ^ (x) * (a) ^ (y) = (a) ^ (x+y).
Anyone from Hyderabad or Telugu speaking community.
Searching for a serious study partner from Hyderabad or the one who work for same Company.
Searching for a serious study partner from Hyderabad or the one who work for same Company.
In the question 3^5 appears thrice: 3^5+3^5+3^5
tohellandback wrote:no. coz 3*3^5=3^(5+1)=3^6mehravikas wrote:Shouldn't it be - 2^6+3^7
truplayer256 wrote:2^5+2^5+3^5+3^5+3^5
2*(2^5)+3*(3^5)=2^(5+1)+3^(5+1)=2^6+3^6
yes and thats why it is 3 * 3^5. Now 3* 3^5=3^6mehravikas wrote:In the question 3^5 appears thrice: 3^5+3^5+3^5
tohellandback wrote:no. coz 3*3^5=3^(5+1)=3^6mehravikas wrote:Shouldn't it be - 2^6+3^7
truplayer256 wrote:2^5+2^5+3^5+3^5+3^5
2*(2^5)+3*(3^5)=2^(5+1)+3^(5+1)=2^6+3^6
The powers of two are bloody impolite!!
Are you trying to say the occurrence of an integer does not matter?
2^5+2^5 = 2^6
3^5+3^5+3^5 = 3^6
2^5+2^5 = 2^6
3^5+3^5+3^5 = 3^6
tohellandback wrote:yes and thats why it is 3 * 3^5. Now 3* 3^5=3^6mehravikas wrote:In the question 3^5 appears thrice: 3^5+3^5+3^5
tohellandback wrote:no. coz 3*3^5=3^(5+1)=3^6mehravikas wrote:Shouldn't it be - 2^6+3^7
truplayer256 wrote:2^5+2^5+3^5+3^5+3^5
2*(2^5)+3*(3^5)=2^(5+1)+3^(5+1)=2^6+3^6
Ummm I am trying to say that its a formula for exponents which can be explained in multiple ways. And I suggest you take any book even the OG and go through the exponents basics once. Should not take more than 20 minutes.mehravikas wrote:Are you trying to say the occurrence of an integer does not matter?
2^5+2^5 = 2^6
3^5+3^5+3^5 = 3^6
tohellandback wrote:yes and thats why it is 3 * 3^5. Now 3* 3^5=3^6mehravikas wrote:In the question 3^5 appears thrice: 3^5+3^5+3^5
tohellandback wrote:no. coz 3*3^5=3^(5+1)=3^6mehravikas wrote:Shouldn't it be - 2^6+3^7
truplayer256 wrote:2^5+2^5+3^5+3^5+3^5
2*(2^5)+3*(3^5)=2^(5+1)+3^(5+1)=2^6+3^6
The powers of two are bloody impolite!!
Thanks..Basically I got confused in a step that was not explained in the answer explanations:
3^5+3^5+3^5 = 3^5(1 + 1 + 1) = 3^5 * 3^1 = 3^6
Cheers,
Vikas
3^5+3^5+3^5 = 3^5(1 + 1 + 1) = 3^5 * 3^1 = 3^6
Cheers,
Vikas
tohellandback wrote:Ummm I am trying to say that its a formula for exponents which can be explained in multiple ways. And I suggest you take any book even the OG and go through the exponents basics once. Should not take more than 20 minutes.mehravikas wrote:Are you trying to say the occurrence of an integer does not matter?
2^5+2^5 = 2^6
3^5+3^5+3^5 = 3^6
tohellandback wrote:yes and thats why it is 3 * 3^5. Now 3* 3^5=3^6mehravikas wrote:In the question 3^5 appears thrice: 3^5+3^5+3^5
tohellandback wrote:no. coz 3*3^5=3^(5+1)=3^6mehravikas wrote:Shouldn't it be - 2^6+3^7
truplayer256 wrote:2^5+2^5+3^5+3^5+3^5
2*(2^5)+3*(3^5)=2^(5+1)+3^(5+1)=2^6+3^6
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Nothing wrong with factoring here, as you did above, to see that 3^5 + 3^5 + 3^5 = 3^6. You can also notice that we're simply adding the same thing three times, which is what it means to multiply by 3:mehravikas wrote:Thanks..Basically I got confused in a step that was not explained in the answer explanations:
3^5+3^5+3^5 = 3^5(1 + 1 + 1) = 3^5 * 3^1 = 3^6
x + x + x = 3x
so 3^5 + 3^5 + 3^5 = 3*(3^5)
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