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pigs and cows

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by mehrasa » Thu Nov 24, 2011 7:45 am
Of the 60 animals on a certain farm, 2/3 are either cows or pigs. How many of the animals are cows?

1) The farm has more than twice as many cows as pigs

2) The farm has more than 12 pigs

[spoiler]OA: C[/spoiler]
but to me, it is E.. this is my approach
c+p=40
c>2p and p>12 ==> c>24 then we have different pairs
25,15
26,14
27,13
28,12
29,11 and.......
the first two can not be the answer since 25 is not larger than 2(15) and the same for 26... but 27,13 and 28, 12 and some other can be fit into these two statements ==> so we can not estimate number of cows....what do u think?
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Source: — Data Sufficiency |
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by shankar.ashwin » Thu Nov 24, 2011 8:01 am
You just contradicted your own solution :)

Statement 2 says more than 12 pigs, so that makes 27 cows, 13 pigs the only possibility.
mehrasa wrote:Of the 60 animals on a certain farm, 2/3 are either cows or pigs. How many of the animals are cows?

1) The farm has more than twice as many cows as pigs

2) The farm has more than 12 pigs

[spoiler]OA: C[/spoiler]
but to me, it is E.. this is my approach
c+p=40
c>2p and p>12 ==> c>24 then we have different pairs
25,15
26,14
27,13
28,12
29,11 and.......
the first two can not be the answer since 25 is not larger than 2(15) and the same for 26... but 27,13 and 28, 12 and some other can be fit into these two statements ==> so we can not estimate number of cows....what do u think?
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by mehrasa » Thu Nov 24, 2011 8:27 am
ohhhhhhhhhhh, ya.. thnx for ur point
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by Anurag@Gurome » Thu Nov 24, 2011 8:05 pm
mehrasa wrote:Of the 60 animals on a certain farm, 2/3 are either cows or pigs. How many of the animals are cows?

1) The farm has more than twice as many cows as pigs

2) The farm has more than 12 pigs

[spoiler]OA: C[/spoiler]
but to me, it is E.. this is my approach
c+p=40
c>2p and p>12 ==> c>24 then we have different pairs
25,15
26,14
27,13
28,12
29,11 and.......
the first two can not be the answer since 25 is not larger than 2(15) and the same for 26... but 27,13 and 28, 12 and some other can be fit into these two statements ==> so we can not estimate number of cows....what do u think?
Let total animals = T
cows = C and Pigs = P
Then (2/3) of 60 = P + C or P + C = 40

(1) C > 2P, It is NOT SUFFICIENT as there can be many possibilities.

(2) P > 12, It is NOT SUFFICIENT as there can be many possibilities.

Combining (1) and (2), If P = 13, then C > 26, so that P + C = 40
If P = 13, C = 27, then P + C = 40 (this is the only possibility)
If P = 14, then C > 28, if C = 29, then P + C = 43, not possible.
There are 27 cows. Hence, SUFFICIENT.

The correct answer is C.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
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