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DS - Odd

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Source: — Data Sufficiency |
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Re: DS - Odd

by fruti_yum » Sat Sep 19, 2009 11:42 am
Xbond wrote:Hi there,

could you help to understand and resolve this PS in the simplest way

you could find enclosed the question

B is sufficient since all of them are integers...
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by Xbond » Sat Sep 19, 2009 2:24 pm
I would like your full explanation, please
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by crackgmat007 » Sat Sep 19, 2009 2:39 pm
Positive integers a, b, c, m, n, and p are defined as follows: m = 2^a * 3^b, n = 2^c, and p = 2m/n. Is p odd?

(1) a < b
(2) a < c
Rephrase:

P = (2 * 2^a * 3^b)/2^c; hence we need to find whether c = a + 1

Stmt 2 states that c > a. With this we can be sure that P is not even. If c is 4, and a is 2, p will not be an integer. If c is 3 and a is 2, then p must be odd.

IMO B
Last edited by crackgmat007 on Fri Sep 25, 2009 11:36 am, edited 1 time in total.
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by Xbond » Thu Sep 24, 2009 11:36 pm
OA is B

For Even/odd the exponent of 3 is irrelevant, so A is out. You look only at the exponenent for 2, which is addressed in choice B This question shoud take less than 30 sec
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