In the sequence shown above, a(n) = a(n-1) + k, where 2 <= n <= 15 and k is a non-zero constant. How many terms in the sequence are greater than 10?
(1) a(1) = 24 (2) a(8) = 10
(1) a(1) = 24 (2) a(8) = 10
Is OA 6??? the question doesn't say that n must be an integer but I'm assuming that...
Because when n = 8 the result is 10, all the values less than n = 8 will yield a result greater than 10. This is n = 2,3,4,5,6,and 7.
I did the math, but I think it's useless in this question
Recursive formula:
a(1) = a(0) + k = 24
a(8) = a(7) + k = 10
a(8) = a(1) + 7k = 10
a(8) = 24 + 7k = 10
7k = 10 - 24
7k = -14
k = -2
Lineal formula:
a(n) = kn + x
a(n) = -2n + x
a(1) = -2 + x = 24
-2 +x = 24
x = 24+2 = 26
Final formula -> a(n) = -2n + 26
atulmangal wrote:In the sequence shown above, a(n) = a(n-1) + k, where 2 <= n <= 15 and k is a non-zero constant. How many terms in the sequence are greater than 10?
(1) a(1) = 24 (2) a(8) = 10
