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by logitech » Tue Nov 04, 2008 5:35 pm
What is the value of y?

(1) 3|x^2 – 4| = y – 2

(2) |3 – y| = 11

OA C
Last edited by logitech on Tue Nov 04, 2008 5:52 pm, edited 1 time in total.
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by cramya » Tue Nov 04, 2008 5:49 pm
3|x2 – 4| = y – 2


IS THIS RIGHT; CAN U PLEAS ECHECK X2 IS x^2 or did u mean Y^2

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Re: 1

by stubbornp » Tue Nov 04, 2008 9:36 pm
logitech wrote:What is the value of y?

(1) 3|x^2 – 4| = y – 2

(2) |3 – y| = 11

OA C

A good one...let's start with stmt 2

|3 – y| = 11

y should be -8 and 14--insufficent

stmt1--no info for x and y--insufficent

combine both,

re arrange 1st statement

y=2 +3|x^2 – 4|

from stmt 2,we ve one -ve and one +ve value...

because equation of x is in absolute

no chance we ll get negative value

anser should be 14---Sufficient

C---hope it clears

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by cramya » Tue Nov 04, 2008 9:45 pm
Nice work Stubbornp.

Stmt II was fine

I was stuck with stmt I.