B = 4/3 A (1/3 faster is 4/3)
= 4/3*3= 4
hope its clear...
Algebra
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Source: Beat The GMAT — Problem Solving |
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sudhir3127
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preetha_85
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Hi ..
Assume A travels at xkm/hr....
B travels 1/3rd faster than A i.e (As spped + (1/3)As speed )
=4/3(As speed)
=(4/3)*3 =4
Hope this clear..
Assume A travels at xkm/hr....
B travels 1/3rd faster than A i.e (As spped + (1/3)As speed )
=4/3(As speed)
=(4/3)*3 =4
Hope this clear..
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parallel_chase
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4/3 is not A's speed, its (4/3)*A's speed2sun3 wrote:How did you get 4/3 as A's speed? Can you explain?
Thanks
if A's speed is 3 miles/hr, and B's speed is 1/3 faster than A's speed.
Then B's speed is (1+1/3) of A's speed
4/3 * (A's speed) = 4 miles/hr
Hope its clear.
Thanks guys for your help.
I'll just want to recap on it to see if i understood it correctly.
If A's speed is 3 miles per hour and B's speed is 1/3 greater than A.
Then assuming if A's speed was 1 Then B's speed would be 1+1/3 = 4/3
But for A's speed=3 then B's speed would be 4/3*3 = 4.
Is that right?
I'll just want to recap on it to see if i understood it correctly.
If A's speed is 3 miles per hour and B's speed is 1/3 greater than A.
Then assuming if A's speed was 1 Then B's speed would be 1+1/3 = 4/3
But for A's speed=3 then B's speed would be 4/3*3 = 4.
Is that right?
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sudhir3127
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