tito1545 wrote:A step by step approach for the below please ?
Whats is the greatest possible area of a triangular region with one vertex at the centre of a circle of radius 1 and the other two vertices on the circle ?
a)Sqrt (3)/4
b)1/2
c)Pi/4
d)1
e)Sqrt(2)
The drawings above show 3 different versions of the triangle.
Leftmost drawing: b=1, h=1.
Middle drawing: b=1, h<1.
Rightmost drawing: b=1, h<1.
Notice that in each triangle b=1, but only in the leftmost triangle does h=1. In the other two triangles, h<1, resulting in a smaller area. The drawings above illustrate the following rule:
Given two sides of triangle, the greatest area will be achieved when a right angle is placed between them. This rule will hold true for any triangle in which we're given 2 sides.
Thus, the leftmost triangle above will yield the greatest area: 1/2 * 1 * 1 = 1/2.
The correct answer is
B.
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then continue with defining the height, which must be a line segment perpendicular to the base it could be radius too; and i think we are done 1/2 *1*1=1/2
