Three dwarves and three elves sit down in a row of six chairs. If no dwarf will sit next to another dwarf and no elf will sit next to another elf, in how many different ways can the elves and dwarves sit? Answer [spoiler]6 × 2 × 1 × 3 × 2 × 1 = 72[/spoiler]
case 1 & 2 can be done in total 36 ways each
3*3*2*2*1*1=36
hence 36+36 =72
sukhman wrote:Three dwarves and three elves sit down in a row of six chairs. If no dwarf will sit next to another dwarf and no elf will sit next to another elf, in how many different ways can the elves and dwarves sit? Answer [spoiler]6 × 2 × 1 × 3 × 2 × 1 = 72[/spoiler]
