number system

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by vinay1983 » Thu Sep 12, 2013 1:36 am
vipulgoyal wrote:if a and b are both positive integers, is b^(a+1) - ba^b
1. a is odd
2. b is even

In source ans is B but i think it is D
Hi can you correct the question?I feel it is incorrect what the question is asking for?
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by vipulgoyal » Thu Sep 12, 2013 3:10 am
I have edited the qustion

Is b^(a+1) - ba^b odd
1. a is odd
2. b is even

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by vinay1983 » Thu Sep 12, 2013 3:30 am
vipulgoyal wrote:if a and b are both positive integers, is b^(a+1) - ba^b
1. a is odd
2. b is even

In source ans is B but i think it is D
I cannot understand this?Please help.What does this mean?

is b^(a+1) - ba^b
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by vipulgoyal » Thu Sep 12, 2013 3:35 am
Is b^(a+1) - ba^b odd

b whole power a+1 - b*a power b
we can simplify

b^a * b - b * a^b
b(b^a - a^b)

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by ganeshrkamath » Thu Sep 12, 2013 3:48 am
vipulgoyal wrote:if a and b are both positive integers, is b^(a+1) - ba^b odd
1. a is odd
2. b is even

In source ans is B but i think it is D
Statement 1. a is odd.
Case 1: b is even. The result will be even - even = even
Case 2: b is odd. The result will be odd - odd = even
Sufficient.

Statement 2. b is even.
The result will be even - even = even
Sufficient.

Choose D

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by [email protected] » Thu Sep 12, 2013 11:50 am
Hi vipulgoyal,

You are correct. The correct answer IS D, not B

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by ceilidh.erickson » Thu Sep 12, 2013 1:20 pm
Several posters have correctly simplified the expression:
b(b^a - a^b)

But let's think further about what it would take for this expression to be ODD. For a product to be odd, both of the terms in that product need to be odd. So b has to be odd; if it's even the whole product would be even.

What would make b^a - a^b odd? Well given that b has to be odd we know that an odd number taken to any positive integer power will also be odd, so b^a is odd. That means that a would have to be even, because ODD - EVEN = ODD.

So the conditions that we need to get an odd product are:
b is odd
a is even

If either of these is violated, we'll get an even product.

1) This violates our second condition. We'd have either:
even(even - odd) = even
odd(odd - odd) = even
Sufficient

2) This violates our first condition. Since we're multiplying b by the terms in the parentheses, that product has to be even.
Sufficient
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