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by sanju09 » Thu May 13, 2010 5:55 am
Each hour, a wood-harvesting machine cuts the same number of logs and places them on a pile. At 8 am, there are 13 logs on the pile. At 11 am, the pile has grown to 46 logs. How many logs will the pile contain at 6 pm, the same evening?
(A) 108
(B) 112
(C) 117
(D) 123
(E) 135
Last edited by sanju09 on Fri May 14, 2010 12:46 am, edited 1 time in total.
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by dtweah » Thu May 13, 2010 7:01 am
8AM 9AM 10 AM 11AM ............. 6PM (18hrs)

13 13 +x 13+2x 13+3x =46..............112

13+3x=46
x=11

t10 ( 18hr -8hr=10) = 13+(10-1)11=112

Choose B
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by GauravMalhotra » Thu May 13, 2010 10:41 am
dtweah wrote:8AM 9AM 10 AM 11AM ............. 6PM (18hrs)

13 13 +x 13+2x 13+3x =46..............112

13+3x=46
x=11

t10 ( 18hr -8hr=10) = 13+(10-1)11=112

Choose B
I am sorry.. I couldn;t quite follow your logic... I was getting answer as 123 which is obviously wrong and so I need to understand how you got 112.
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by harshavardhanc » Thu May 13, 2010 11:27 am
me too 123.... :(

is there something wrong?
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Harsha
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by debmalya_dutta » Thu May 13, 2010 11:38 am
I got 123 too .

:(
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by Stuart@KaplanGMAT » Thu May 13, 2010 12:04 pm
sanju09 wrote:Each hour, a wood-harvesting machine cuts the same number of logs and places them on a pile. At 8 am, there are 13 logs on the pile. At 11 am, the pile has grown to 46 logs. How many logs will the pile contain at 6 pm, the same evening?
(A) 108
(B) 112
(C) 117
(D) 126
(E) 135
46-13 is 33. 33 logs in 3 hours is 11 logs/hour.

From 11am until 6pm there are 7 hours. 7 * 11 = 77 new logs.

46 + 77 = 123, which is the correct answer to the question. What's the source?
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by cager » Thu May 13, 2010 12:09 pm
i got 123
112 does not take into account the amount of logs made between 8am and 9am (according to the formula "13+(10-1)*11"
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by sanju09 » Fri May 14, 2010 12:45 am
Sorry pals for appearing so late on this thread, the OA is [spoiler](D) 123[/spoiler], which is by some typo, 126 there, I will edit it.

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