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absolute confusion

by dikku07 » Thu Sep 24, 2009 10:49 am
Is �x�< 1?


(1) �!x + 1!� = 2�!x - 1!�
(2) �!x - 3!� ≠ 0

! is used to denote abolute value bar.
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Source: — Data Sufficiency |
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by sunnyjohn » Thu Sep 24, 2009 10:05 pm
considering your Question as:
Is |x| < 1 ?

a) -- > |x+1| = 2|x-1|
b) ---> |x-3| ≠ 0

Solution:

|x|< 1 ==> -1<x<1

Option A)
(x+1) = 2(x-1) ==> x = 1/3
(x+1) = -2(x-1) ==> x = 3

so not sufficient

Option B):-
x ≠ 3

Not sufficient

combine A and B:)
x = 1/3 ==> so sufficient

so answers should be C.
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by dikku07 » Sat Sep 26, 2009 6:29 am
OA is C
could you pls break the first statement and describe how did you arrive at x=1/3 :shock:
is it is
(x+1)=2(x-1), I get x=3 and not 1/3

thanks
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by sunnyjohn » Sat Sep 26, 2009 6:58 am
Oops, I wrote it by mistake, it should be:

x + 1 = -2x + 2

==> 3x = 1

==> x = 1/3

So Please read it like:

Option A)
(x+1) = 2(x-1) ==> x = 3
(x+1) = -2(x-1) ==> x = 1/3
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