Is the answer E?

IMO C.

Please explain ur answers.

I would say B

For |x-3| to be <= -y , y has to be 0 and X has to be 3.

Nithi is correct. It's B.

nithi_mystics wrote:I would say B

For |x-3| to be <= -y , y has to be 0 and X has to be 3.

Please elaborate ur answer.

selango wrote:If y>= 0, what is the value of x?

1. |x-3| >= y
2. |x-3| <= -y

OA later

I'll let Nithi further explain his (or her, sorry!) answer, but I wanted to make a point about strategic guessing in DS. Let's look at statement (1):

|x-3| >= y

combined with the stem, which tells us that y>=0, we have:

|x-3| >= 0

Well, the absolute value of something is always greater than or equal to 0. Accordingly, (1) is of absolutely no value.

When (1) is merely insufficient, we eliminate A and D. When (1) is 100% worthless, we eliminate A, D and C.

So, as soon as you realize that (1) provides no new information, you have a 50/50 shot of getting the question right even if you don't understand (2).

selango wrote:If y>= 0, what is the value of x?

1. |x-3| >= y
2. |x-3| <= -y

OA later

Y is +ve number or 0. -Y will be a -ve number or 0.
2. |x-3| <= -y
|x-3| is always +ve as a whole. so, it cannot be -ve.

This suggests that -Y can only be 0.

|x-3| = 0, which means x = 3. SUFFICIENT

What is the source of this question ? Its very neatly designed and gives me an impression of a currently running question on GMAT.

OA B

While searching for old problems here in DS section,I came across this question.[Topic is GMATPREP question]

I think this is one of the old GMATPREP questions.

This is the sort of problem on which I'll make a "stupid" mistake. I quickly saw that statement 1 was insufficient. However, instead of immediately seeing whether statement 2 was sufficient by itself, I first looked at whether the combination of the two statements was sufficient. Sure enough, the two statements combined are sufficient to solve the problem, so I incorrectly stopped there, and selected 'C'. Bad strategy on my part.