- ithamarsorek
- Junior | Next Rank: 30 Posts
- Posts: 26
- Joined: Tue Dec 07, 2010 1:01 pm
st(2) n<6 (5,4,3,2,1); 5=a-2 (a is 7), 4=a-7 (a is 11), 3=a-2 (a is 5), 2=a-11 (a is 13), 1=a-2 (a is 3) Sufficient;
answer B
ithamarsorek wrote:1st part: If they tell me that n is odd, it can be any one of these prime numbers and 2. So why is that incorrect, because it can also be just any of these primes and then it is even?
2nd part: you mean, because we know the range must be less then 6 need to figure which primes under 30 makes n<6 and if there are any? 19-17, 23-19, 3-2, etc... If we find that this kind of #s exist then the statement is correct?
So basically (statement 1 - can be odd or even / no guarantee, statement 2 - must be <6 then we know that those primes are available) ?