350 - 77 = 273 (1 term of value 77)
273/7 = 39 (39 terms of value 7)
1 + 39 = 40
Choose(c).
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GMATPrep series question? 7..77..e.t.c.
Source: Beat The GMAT — Data Sufficiency |
Thanks. But why did you subtract 77 only once? There could be more than one 77. Why did you assume that there is only one 77?
Thanks
M
Thanks
M
ur rite when u ask y subtract 77 only once.........
The GMAT wants an answer from the choices given......you can try to subtract 77 more than once but u will be left with a number which is not divisible by 7..........also the more u subtract 77 the lesser will the number of terms become..........subtracting 77 twice will reduce the terms by 20 which is not among the options
another way of solving the problem is 350/7 = 50.......77 is 7X11.......so one 77 will reduce the number of terms by 11.......so ur left with 39.......but 77 is also one term and hence the number of terms is 39+1=40
Hope you got it!!!!!
The GMAT wants an answer from the choices given......you can try to subtract 77 more than once but u will be left with a number which is not divisible by 7..........also the more u subtract 77 the lesser will the number of terms become..........subtracting 77 twice will reduce the terms by 20 which is not among the options
another way of solving the problem is 350/7 = 50.......77 is 7X11.......so one 77 will reduce the number of terms by 11.......so ur left with 39.......but 77 is also one term and hence the number of terms is 39+1=40
Hope you got it!!!!!
Here's my solution
k=> the no of terms = 77
n-k=> the no of terms = 7
the sum a1+...an = 7(n-k) + 77k = 7n-7k+77k=7n+70k=350
So n+10k=50
k and n must be integers, so k can be {1...5} and n can be {10, 20, 30, 40, 50}
Hence n=40
k=> the no of terms = 77
n-k=> the no of terms = 7
the sum a1+...an = 7(n-k) + 77k = 7n-7k+77k=7n+70k=350
So n+10k=50
k and n must be integers, so k can be {1...5} and n can be {10, 20, 30, 40, 50}
Hence n=40
