Henry purchase 3 items during a sale. He received a 20 percent discount off the regular price of the most
expensive item and a 10 percent discount off the regular price of each of the other 2 items. Was the total
amount of the 3 discounts greater than 15 percent of the sum of the regular prices of the 3 items?
(1) The regular price of the most expensive item was $50, and the regular price of the next most expensive
item was $20
(2) The regular price of the least expensive item was $15.
This is a weighted average question.
How can we combine a 20% discount with a 10% discount to yield a combined discount that is more than 15%?
If the price discounted at 20% equals the sum of the prices discounted at 10%, the resulting discount will be exactly 15%.
Thus, to yield a discount that is more than 15%, the price discounted at 20% must be greater than the sum of the prices discounted at 10%.
Rephrased, the question is asking:
Is the regular price of the most expensive item greater than the sum of the regular prices of the two cheaper items?
Statement 1: The regular price of the most expensive item was $50, and the regular price of the next most expensive
item was $20.
The sum of the prices of the 2 cheaper items cannot be greater than 20+20 = 40.
Thus, the $50 price of the most expensive item must be greater than the sum of the prices of the 2 cheaper items.
Sufficient.
Statement 2: The regular price of the least expensive item was $15.
No way to determine whether the price of the most expensive item is greater than the sum of the prices of the 2 cheaper items.
Insufficient.
The correct answer is
A.
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