As per Statement 1 ,the operation can be addition or multiplication since 3*2>3 and 3+2>3
Hence the operations will give identical results irrespective of their orders that is,
(a*b)*c=a*(b*c) and
(a+b)+c=a+(b+c)
So statement 1 satisfies the criteria
From statement 2 we can infer that the operation is either multiplication or division
Although multiplication will give identical results even if order is changed,results will differ in case of division.
that is (a /b)/c <>a/(b/c)
So statement 1 alone is sufficient

given "/\" can be +,-,/ or *.

1) 3/\2>3
this implies either /\ is + or *
now we have to solve for (6/\2)/\4 =6/\(2/\4)

This can be true for both + or * hence 1 is sufficient. Now we can discard options C , E and B The only option that can be there other than A is D

2) 3/\1 = 3
implies /\ can be *or division
* will give the answer but what about division
lets try it LHS is (6/2)/4 = 3/4
RHS is 6/(2/4)= 6*4/2 = 12

For all DS questions try to check a statement at a time, if you can solve with one statement then you can automatically discard C, E option and the only other option other than the valid statement is D.