x<y. Is x<0?
1) x^2>y^2
2) x ^ 3> y ^ 3
123) Is x<0?
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- ballubalraj
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Stmt 1: If x < y, then x^2 > y^2 can be true only if x is negative; sufficient
Stmt 2: If x < y,then x^3 > y^3 can be true only if x = 0; sufficient
Ans D.
Note: As no information is mentioned about x and y, I assumed that zero is an acceptable values for x.
Any expert comments on this?
Stmt 2: If x < y,then x^3 > y^3 can be true only if x = 0; sufficient
Ans D.
Note: As no information is mentioned about x and y, I assumed that zero is an acceptable values for x.
Any expert comments on this?
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1 - For any positive x and y. There is no x and y combination where x^2 > y^2 and x < y are both satisfied. If x is negative and y positive we can have both conditions met. If x is negative and y is also negative, y has to be greater than x for both conditions to hold. Thus, 1 is sufficient, as x<0 is always the case.
2 - For x^3 > y^3, means x > y, but the question says x<y. Thus there is no solution.
Hence, my bet is A
OA please .......?
2 - For x^3 > y^3, means x > y, but the question says x<y. Thus there is no solution.
Hence, my bet is A
OA please .......?
- ballubalraj
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