a ps from gmatclub

This topic has expert replies
Legendary Member
Posts: 1119
Joined: Fri May 07, 2010 8:50 am
Thanked: 29 times
Followed by:3 members

a ps from gmatclub

by diebeatsthegmat » Mon Jun 13, 2011 12:55 pm
If Dev works alone he will take 20 more hours to complete a task than if he worked with Tina to complete the task. If Tina works alone, she will take 5 more hours to complete the complete the task, then if she worked with Dev to complete the task? What is the ratio of the time taken by Dev to that taken by Tina if each of them worked alone to complete the task?
Source: — Problem Solving |

User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pm
Location: New York, NY
Thanked: 13060 times
Followed by:1906 members
GMAT Score:790

by GMATGuruNY » Mon Jun 13, 2011 1:49 pm
diebeatsthegmat wrote:If Dev works alone he will take 20 more hours to complete a task than if he worked with Tina to complete the task. If Tina works alone, she will take 5 more hours to complete the complete the task, then if she worked with Dev to complete the task? What is the ratio of the time taken by Dev to that taken by Tina if each of them worked alone to complete the task?
Difference between time for Tina alone and time for Dev alone = 20-5 = 15 hours.
We can plug in times for Tina alone and for Dev alone until we find a combination that works.
Given that all the numbers in the problem are multiples of 5, the correct times for Tina alone and for Dev alone will probably also be multiples of 5.

Let Tina alone = 10 hours, Dev alone = 25 hours.
Let job = 50 units.
Rate for Tina alone = w/t = 50/10 = 5 units per hour
Rate for Dev alone = w/t = 50/25 = 2 units per hour.
Combined rate for Tina and Dev = 5+2 = 7 units per hour.
The job (50 units) is not a multiple of the combined rate (7).
Doesn't work.

Let Tina alone = 15 hours, Dev alone = 30 hours.
Let job = 30 units.
Rate for Tina alone = w/t = 30/15 = 2 units per hour
Rate for Dev alone = w/t = 30/30 = 1 unit per hour.
Combined rate for Tina and Dev = 2+1 = 3 units per hour.
Time for Tina and Dev together = w/r = 30/3 = 10 hours.

Success! Both conditions are satisfied:
Time for Tina alone - Time for Tina and Dev together = 15-10 = 5 hours.
Time for Dev alone - Time for Tina and Dev together = 30-10 = 20 hours.

Answer:
Time for Dev alone : time for Tina alone = 30:15 = 2:1.

Here's an algebraic approach:

Let t = time for Dev and Tina working together.

Rate for Dev and Tina together = 1/t
Rate for Dev alone = 1/(t+20)
Rate for Tina alone = 1/(t+5)

Rate for Dev alone + Rate for Tina alone = Rate for Dev and Tina together:
1/(t+20) + 1/(t+5) = 1/t

(t+5)+(t+20) / (t+20)(t+5) = 1/t

(2t + 25) / (t² + 25t + 100) = 1/t

Cross-multiplying, we get:

2t² + 25t = t² + 25t + 100
t² = 100
t = 10.

Time for Dev alone = t+20 = 10+20 = 30.
Time for Tina alone = t+5 = 10+5 = 15.
Ratio = 30:15 = 2:1.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3

User avatar
Master | Next Rank: 500 Posts
Posts: 233
Joined: Mon Jun 09, 2008 1:30 am
Thanked: 5 times

by blaster » Mon Jun 13, 2011 10:25 pm
love instructors this kind of approch :) a wasted about 13 min. solving this question, but Mitch did this within 2 min, just picking numbers. cool!

Legendary Member
Posts: 1119
Joined: Fri May 07, 2010 8:50 am
Thanked: 29 times
Followed by:3 members

by diebeatsthegmat » Tue Jun 14, 2011 7:13 pm
GMATGuruNY wrote:
diebeatsthegmat wrote:If Dev works alone he will take 20 more hours to complete a task than if he worked with Tina to complete the task. If Tina works alone, she will take 5 more hours to complete the complete the task, then if she worked with Dev to complete the task? What is the ratio of the time taken by Dev to that taken by Tina if each of them worked alone to complete the task?
Difference between time for Tina alone and time for Dev alone = 20-5 = 15 hours.
We can plug in times for Tina alone and for Dev alone until we find a combination that works.
Given that all the numbers in the problem are multiples of 5, the correct times for Tina alone and for Dev alone will probably also be multiples of 5.

Let Tina alone = 10 hours, Dev alone = 25 hours.
Let job = 50 units.
Rate for Tina alone = w/t = 50/10 = 5 units per hour
Rate for Dev alone = w/t = 50/25 = 2 units per hour.
Combined rate for Tina and Dev = 5+2 = 7 units per hour.
The job (50 units) is not a multiple of the combined rate (7).
Doesn't work.

Let Tina alone = 15 hours, Dev alone = 30 hours.
Let job = 30 units.
Rate for Tina alone = w/t = 30/15 = 2 units per hour
Rate for Dev alone = w/t = 30/30 = 1 unit per hour.
Combined rate for Tina and Dev = 2+1 = 3 units per hour.
Time for Tina and Dev together = w/r = 30/3 = 10 hours.

Success! Both conditions are satisfied:
Time for Tina alone - Time for Tina and Dev together = 15-10 = 5 hours.
Time for Dev alone - Time for Tina and Dev together = 30-10 = 20 hours.

Answer:
Time for Dev alone : time for Tina alone = 30:15 = 2:1.

Here's an algebraic approach:

Let t = time for Dev and Tina working together.

Rate for Dev and Tina together = 1/t
Rate for Dev alone = 1/(t+20)
Rate for Tina alone = 1/(t+5)

Rate for Dev alone + Rate for Tina alone = Rate for Dev and Tina together:
1/(t+20) + 1/(t+5) = 1/t

(t+5)+(t+20) / (t+20)(t+5) = 1/t

(2t + 25) / (t² + 25t + 100) = 1/t

Cross-multiplying, we get:

2t² + 25t = t² + 25t + 100
t² = 100
t = 10.

Time for Dev alone = t+20 = 10+20 = 30.
Time for Tina alone = t+5 = 10+5 = 15.
Ratio = 30:15 = 2:1.
cooolll thank you