If 5 is a divisor of m and 7 is a divisor of n, what is the value of n?
(1) mn is 140
(2) n is an even integer.
IMO E
OA is C
because Lets say m=5K
and n=7K' where K and K' are quotients.
from st.1 we gat that mn=5.7.K.K'=140=>K.K'=140/35=4
this 4 could be (2x2) or (4x1) or (1x4)
from this it is insufficient to tell n
from st.2 we get n=7K' is Even. we cant say any thing from it so it is insufficient.
By taking both st.-as 7 is odd so K'has to be even in oredr to n=7K' to be even. so K' could be 2 or 4
still insufficient.
It must be E
(1) mn is 140
(2) n is an even integer.
IMO E
OA is C
because Lets say m=5K
and n=7K' where K and K' are quotients.
from st.1 we gat that mn=5.7.K.K'=140=>K.K'=140/35=4
this 4 could be (2x2) or (4x1) or (1x4)
from this it is insufficient to tell n
from st.2 we get n=7K' is Even. we cant say any thing from it so it is insufficient.
By taking both st.-as 7 is odd so K'has to be even in oredr to n=7K' to be even. so K' could be 2 or 4
still insufficient.
It must be E
