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Five friends play blackjack in Las Vegas and lose an average

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by AAPL » Sat Jun 01, 2019 7:21 am

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Princeton Review

Five friends play blackjack in Las Vegas and lose an average of $100 each. If the losses of two of the friends total $380, what is the average loss of the other friends?

A. $40
B. $60
C. $100
D. $120
E. $1,900

OA A
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Source: — Problem Solving |

by Jay@ManhattanReview » Mon Jun 03, 2019 4:11 am
AAPL wrote:Princeton Review

Five friends play blackjack in Las Vegas and lose an average of $100 each. If the losses of two of the friends total $380, what is the average loss of the other friends?

A. $40
B. $60
C. $100
D. $120
E. $1,900

OA A
Given that the average is $100 each, total loss of five friends = 5*100 = $500.

It is also given that two friends lost a total of $380; thus, the other three friends together have lost 500 - 380 = $120.

Thus, the average loss of the other three friends = 120/3 = $40.

The correct answer: A

Hope this helps!

-Jay
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by Scott@TargetTestPrep » Thu Jun 06, 2019 4:40 pm
AAPL wrote:Princeton Review

Five friends play blackjack in Las Vegas and lose an average of $100 each. If the losses of two of the friends total $380, what is the average loss of the other friends?

A. $40
B. $60
C. $100
D. $120
E. $1,900

OA A
The total loss of all the friends is 500 dollars. Since two friends lost 380 dollars, the remaining 3 friends lost a total of 120 dollars, or an average of 120/3 = 40 dollars.

Answer: A

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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