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If n is a multiple of 5 and n= p^2q ...

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by qduong » Wed Jun 01, 2011 11:22 pm
If n is a multiple of 5 and n= p^2q , where p and q are prime numbers, which of the following must be a multiple of 25 ?

a. p^2
b. q^2
c. pq
d. p^2q^2
e. p^3q

Please explain. Thank you !
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by cans » Wed Jun 01, 2011 11:40 pm
I have a doubt.
Is it n=p^(2q) or n=p^2 * q??
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by smackmartine » Wed Jun 01, 2011 11:45 pm
IMO D

D is the only option in which we get "5" twice , making it a multiple of 25.
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by cans » Thu Jun 02, 2011 12:24 am
assuming its p^2 * q
either q=5 or p=5
a)p^2 - if q=5 then not valid
b)q^2 - if p=5, then not valid
c) pq - if p=5, then multiple of 5 and not 25
d) p^2*q^2 - if p=5, then multiple of 25. if q=5, then multiple of 25. valid
e) p^3*q - if q=5, then multiple of 5 and not 25.
IMO D
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by qduong » Thu Jun 02, 2011 12:44 am
cans wrote:I have a doubt.
Is it n=p^(2q) or n=p^2 * q??
it is n=p^2 * q

thank you for your reply !
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by [email protected] » Mon Jun 13, 2011 6:15 am
wonderful explanation cans!!!!
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