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Number Prop

Expert replies
Source: — Data Sufficiency |

by pemdas » Sun Jul 10, 2011 1:31 am
p/(q^2)=?
st(1) p/(q^2)=c where c is a positive integer. Not Sufficient as c can be anything;
st(2) q/p=b where b is a positive integer and p=bq. Not Sufficient as p/(q^2)=bq/(q^2)=b/q and b can be any value
combined st(1&2): b/q=c, q=b/c --> from st(2) q=bp hence bp=b/c, p=1/c; from st(1) p=c*(q^2) hence 1/c=c*(q^2), 1=(cq)^2 since positive numbers cq=1 and p/(q^2)=c <> p=c*q^2, p=1*q or p=q

p/(q^2)=1/q <> b/q=1/q and b=1 with b/q=c, 1/q=c can be positive integer only if q=1

p/(q^2)=1, Sufficient

c
artstudent wrote:If p and q are positive integers, what is the value of p/(q^2)?

(1) p is a multiple of q^2.

(2) q is a multiple of p.
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by Mom4MBA » Tue Jul 12, 2011 9:00 pm
Hi pemdas,
p/(q^2)=?
st(1) p/(q^2)=c where c is a positive integer. Not Sufficient as c can be anything;
st(2) q/p=b where b is a positive integer and p=bq . Not Sufficient as p/(q^2)=bq/(q^2)=b/q and b can be any value
combined st(1&2): b/q=c, q=b/c --> from st(2) q=bp hence bp=b/c, p=1/c; from st(1) p=c*(q^2) hence 1/c=c*(q^2), 1=(cq)^2 since positive numbers cq=1 and p/(q^2)=c <> p=c*q^2, p=1*q or p=q

p/(q^2)=1/q <> b/q=1/q and b=1 with b/q=c, 1/q=c can be positive integer only if q=1

p/(q^2)=1, Sufficient
how did you get p=bq? it is given that " q is a multiple of p," not " p is a multiple of q."
can you please explain?
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by amit2k9 » Tue Jul 12, 2011 11:09 pm
a p= kq^2. hence k can be any positive value.

b q=mp hence p/(mp)^2 = 1/m^2*p. not sufficient.


a+b

p= k* m^2 * p^2. since k and m will be positive value and integers. thus p=1 for q=1.
(gives p=0 or pkm^2=1.)

hence C is sufficient.
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