Search found 27 matches
- by abkhan
Mon Sep 03, 2007 10:50 pm- Forum: Data Sufficiency
- Topic: Value of w
- Replies: 3
- Views: 2091
let area of first triangle be A and B. A=2B --5 let height of A be P and B be H for first triangle A= P.S/2 --1 tan x = P/S --2 for second triangle B=H.s/2 --3 tan x= H/s --4 equating 2 = 4 -> P/S=H/s -> P/H=S/s equating 5 -> A=2B -> replacing 1 and 3 -> P.S/2=2.H.s/2 -> P/H=2.s/S -> S/s=2.s/S -> S^...
- by abkhan
Mon Sep 03, 2007 10:11 pm- Forum: Problem Solving
- Topic: GMAT Prep - Geometry
- Replies: 7
- Views: 10901
so sorry .. i misunderstood the question . Was looking for 6^n in 324 where as we should be looking for 324 in 6^n..
- by abkhan
Tue May 22, 2007 4:21 am- Forum: Problem Solving
- Topic: prep question
- Replies: 6
- Views: 3541
sorry but cybermusing seems easier. try breaking any given number into prime numbers. they tend to show a much more clearer relation
5^21 * 4^11 = 2 * 10^n
=> 5^21 * (2^2)^11 = 2 * 10^n
=> 5^21 * 2^22 = 2 * 10^n
=> 2 * 10^21 = 2 * 10^n
equating n on both sides
we have n=21
- by abkhan
Mon May 21, 2007 5:11 am- Forum: Problem Solving
- Topic: stuck on exponents
- Replies: 4
- Views: 1843
- by abkhan
Mon May 21, 2007 4:57 am- Forum: Sentence Correction
- Topic: 878 - can anyone confirm the answer?
- Replies: 15
- Views: 7795
What is the smallest positive integer n for which 324 is a factor of 6^n? A. 2 B. 3 C. 4 D. 5 E. 6 6^1 = (2^1)*(3^1) 6^n = (2^n)*(3^n) 324 = (2^2)*(3^4) So if 324 is a factor it should divide 6^n completely (without any remainder) 6^n / [(2^2)*(3^4)] = An Interger Thus n's minimum value is 4 f20012...
- by abkhan
Mon May 21, 2007 1:46 am- Forum: Problem Solving
- Topic: prep question
- Replies: 6
- Views: 3541
- by abkhan
Mon May 21, 2007 1:18 am- Forum: 2007 Scholarships
- Topic: Winners Selected!
- Replies: 12
- Views: 7082
oh .. u mean the condition to be satissifed is if b is (x,y) then distance between them
x^2 +y^2=100 must be satisfied
- by abkhan
Mon May 21, 2007 1:13 am- Forum: Problem Solving
- Topic: MGMAT - total number of squares
- Replies: 7
- Views: 2212
- by abkhan
Sun May 20, 2007 8:54 am- Forum: Problem Solving
- Topic: Another question
- Replies: 2
- Views: 1502
Unfortunately, my only explanation is drawing from what I read during GMAT prep a few months ago. Apparently the Pythagorean triangle that appears most frequently on the exam are those with sides of lengths 3:4:5 or multiples of such. I spent probably 15+ minutes trying to figure out how to even ap...
- by abkhan
Sun May 20, 2007 8:50 am- Forum: Problem Solving
- Topic: MGMAT - triangles
- Replies: 6
- Views: 2091
If a line is equi-distant from two points doesn't mean that it is passing through the middle. for example, if the two points lie on the same side of the line and are equidistant, then mid-point formula doesn't help . Your right, i tried that approach but the data seemed insufficient if we take that...
- by abkhan
Sun May 20, 2007 8:08 am- Forum: Problem Solving
- Topic: MGMAT - slope of line
- Replies: 9
- Views: 2551
Since a Fixed cost of 20$ dollars plus twice the cost af a x cycle in first week will always be involved the product of y cycle in second week and cost of each should always be greater.
also y>x always.
answer is E.
please tell what i left out if am wrong
- by abkhan
Sun May 20, 2007 2:47 am- Forum: Problem Solving
- Topic: MGMAT - bicycle sales
- Replies: 4
- Views: 2966
As said above it is important to see that it is the equation which is inside the mod value |a+4| not just a. This changes the question .
- by abkhan
Sun May 20, 2007 2:05 am- Forum: Data Sufficiency
- Topic: DS question
- Replies: 4
- Views: 2501
Since area must be 100 possible porduct are = 10 * 10 only so a line must of length 10 since it is to be a square, We get four square's with vertices on origin and square in each quadrant only . The diagonal length is = 2* (10)^(1/2) This is not an integer. so diagonals wont be on axis with integral...
- by abkhan
Sun May 20, 2007 1:56 am- Forum: Problem Solving
- Topic: MGMAT - total number of squares
- Replies: 7
- Views: 2212
let equation of line be = > y=mx+c
Since it passes origin (0,0) on replacing (x,y)
we have
=>y=mx
Mid point is ( (1+7)/2,(11+9)/2)= (4,9)
replacing in above eq. we have m= 2.25
so slope is 2.25
- by abkhan
Sun May 20, 2007 1:41 am- Forum: Problem Solving
- Topic: MGMAT - slope of line
- Replies: 9
- Views: 2551